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3x^2+10=6x-9
We move all terms to the left:
3x^2+10-(6x-9)=0
We get rid of parentheses
3x^2-6x+9+10=0
We add all the numbers together, and all the variables
3x^2-6x+19=0
a = 3; b = -6; c = +19;
Δ = b2-4ac
Δ = -62-4·3·19
Δ = -192
Delta is less than zero, so there is no solution for the equation
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